PHYSICS
COLLEGE

Answer:

Answer:

46292640.48 N

Explanation:

a = Accelration of the water = 0

A = Cross sectional area =

= Density of water =

u = Velocity of water = 12 m/s

V = Volume of body =

= Drag coefficient = 0.73

= Inertia coefficient = 0.34

The force exerted on the leg of the platform is 46292640.48 N

HIGH SCHOOL

In an atom where are the electrons with less energy most likely located?

We have to be very careful here !

An electron that has any energy can go galavanting around on its own, sight-seeing

and doing its own thing. That's not the situation with the electrons in an atom. The

energy of every electron in an atom is negative ... it "owes" the atom energy, and

that's why it stays bound to it. You have to pull on the electron ... give it some more

energy ... in order to break it free from the atom.

The electrons that are way out in the outer orbits are the easiest to rip away from the

atom ... they don't "owe" the atom much, their energy is the least negative, and you

don't have to give them much to settle their debt and release them from the atom.

The electrons that are down deep, closest to the nucleus, are the most tightly bound.

They're the ones whose energy is the most negative, and it takes a team of horses to

pull them free of the atom.

I know I'm going to catch flak for this answer, but I do believe it's the most technically

correct one: The electrons with the least energy are the ones whose energy is most

negative ... those in the first orbital, down deep in the atom, close to the nucleus.

An electron that has any energy can go galavanting around on its own, sight-seeing

and doing its own thing. That's not the situation with the electrons in an atom. The

energy of every electron in an atom is negative ... it "owes" the atom energy, and

that's why it stays bound to it. You have to pull on the electron ... give it some more

energy ... in order to break it free from the atom.

The electrons that are way out in the outer orbits are the easiest to rip away from the

atom ... they don't "owe" the atom much, their energy is the least negative, and you

don't have to give them much to settle their debt and release them from the atom.

The electrons that are down deep, closest to the nucleus, are the most tightly bound.

They're the ones whose energy is the most negative, and it takes a team of horses to

pull them free of the atom.

I know I'm going to catch flak for this answer, but I do believe it's the most technically

correct one: The electrons with the least energy are the ones whose energy is most

negative ... those in the first orbital, down deep in the atom, close to the nucleus.

HIGH SCHOOL

Which of the following is defined as displacement over change in time? A. Speed

B. Acceleration

C. Velocity

D. Displacement

the answer is B Acceleration

MIDDLE SCHOOL

What is the circumference of the moon?

The diameter of the moon is about 2,161 miles or (3,476 kilometers).that makes the circumference about 6,790 miles

The circumference of the moon is 6,786 mi

COLLEGE

A uniform 40-N board supports two children weighing 500 N and 350 N. If the support is at the center of the board and the 500-N child is 1.5 m from its center, How far is the 350-N child from the center?

Answer:

b= 2.14 m

Explanation:

Given that

Weight of the board ,wt = 40 N

Wight of the first children , wt₁=500 N

Weight of the second children ,wt₂ = 350 N

The distance of the 500 N child from center ,a= 1.5 m

lets take distance of the 350 N child from center = b m

Now by taking the moment about the center of the board

We know that moment = Force x Perpendicular distance from the force

wt₁ x a = wt₂ x b

500 x 1.5 = 350 x b

b= 2.14 m

Therefore the distance of the 350 N weight child from the center is 2.14 m.

HIGH SCHOOL

Copper has a specific heat of 0.386 J/g°C. How much heat is required to increase 5.00 g of copper from 0.0°C to 10.0°C?

Heat required = 0.386 * 5.00 * (10-0) = 19.3 J

HIGH SCHOOL

A 64.6-kg boy and a 49.1-kg girl, both wearing skates face each other at rest on a skating rink. The boy pushes the girl, sending her eastward with a speed of 3.57 m/s. Determine the subsequent speed (in m/s) of the boy. a. 2.7 m/s

b. 4.7 m/s

c. 31.8 m/s

Answer:

a. 2.7 m/s

Explanation:

Total momentum must be conserved before and after the push. Since they were both at rest before, their total speed, and momentum, is 0, so is the total momentum after the push

where are the mass of the boy and girl, respectively. are the velocities of the girl and boy after the push, respectively. We can solve for

So the boy speed is 2.7 m/s after pushing the girl

COLLEGE

a pulley of diameter 15.0 cm is driven by a motor that revolves at 10 rpm. the pulley drives a 2nd pulley with diameter 10.0 cm. find the rpm of the 2nd pulley

6.67prm

diam1/diam2 = rpm1/rpm2

diam1/diam2 = rpm1/rpm2

HIGH SCHOOL

During a free fall Swati was accelerating at -9.8m/s^2. After 120 seconds how far did she travel? Use the formula =1/2 * t^2 to solve your answer. (Do not forget to keep units in your answer.)

Answer: 70.56 km

From the Equation of motion:

where, is the distance covered, is the initial speed, is the acceleration and is the time.

In the question it is given that the Swati was in a free fall. This means that her initial velocity is 0 and she is just falling due to gravity. It means she is experiencing acceleration due to gravity. for time

Substitute the values in the equation of motion:

(ignore the negative sign)

COLLEGE

A small car with mass 0.800 kg travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m. if the normal force exerted by the track on the car when it is at the top of the track (point b.is 6.00 n, what is the normal force on the car when it is at the bottom of the track (point a)?

I believe the answer is b .......