PHYSICS COLLEGE

Using the variable definitions​ above, compute the force exerted on a single​ leg, of a perfectly stationary​ platform, by waves moving at a velocity of 12 ​m/s. The waves are not accelerating at and the coefficients of drag and inertia are 0.73 and 0.34​, respectively. The cross sectional area of one leg is 879 msquared and the volume of a leg is 9813 mSuperscript nothingcubed. The density of the water is 1002 ​kg/mcubed. Compute the force exerted on the leg of the platform.

Answers

Answer 1
Answer:

Answer:

46292640.48 N

Explanation:

a = Accelration of the water = 0

A = Cross sectional area =

= Density of water =

u = Velocity of water = 12 m/s

V = Volume of body =

= Drag coefficient = 0.73

= Inertia coefficient = 0.34

The force exerted on the leg of the platform is 46292640.48 N


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In an atom where are the electrons with less energy most likely located?

Answers

We have to be very careful here !

An electron that has any energy can go galavanting around on its own, sight-seeing
and doing its own thing. That's not the situation with the electrons in an atom.  The
energy of every electron in an atom is negative ... it "owes" the atom energy, and
that's why it stays bound to it. You have to pull on the electron ... give it some more
energy ... in order to break it free from the atom.

The electrons that are way out in the outer orbits are the easiest to rip away from the
atom ... they don't "owe" the atom much, their energy is the least negative, and you
don't have to give them much to settle their debt and release them from the atom.

The electrons that are down deep, closest to the nucleus, are the most tightly bound.
They're the ones whose energy is the most negative, and it takes a team of horses to
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I know I'm going to catch flak for this answer, but I do believe it's the most technically
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HIGH SCHOOL

Which of the following is defined as displacement over change in time? A. Speed


B. Acceleration


C. Velocity


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 the answer is B Acceleration
MIDDLE SCHOOL

What is the circumference of the moon?

Answers

The diameter of the moon is about 2,161 miles or (3,476 kilometers).that makes the circumference about 6,790 miles

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COLLEGE

A uniform 40-N board supports two children weighing 500 N and 350 N. If the support is at the center of the board and the 500-N child is 1.5 m from its center, How far is the 350-N child from the center?

Answers

Answer:

b= 2.14 m

Explanation:

Given that

Weight of the board ,wt = 40 N

Wight of the first children , wt₁=500 N

Weight of the second children ,wt₂ = 350 N

The distance of the 500 N child from center ,a= 1.5 m

lets take distance of the 350 N child from center = b m

Now by taking the moment about the center of the board

We know that moment = Force x Perpendicular distance from the force

wt₁ x a = wt₂ x b

500 x 1.5 = 350 x b

b= 2.14 m

Therefore the distance of the 350 N weight child from the center is 2.14 m.

HIGH SCHOOL

Copper has a specific heat of 0.386 J/g°C. How much heat is required to increase 5.00 g of copper from 0.0°C to 10.0°C?

Answers

Heat required = 0.386 * 5.00 * (10-0) = 19.3 J
HIGH SCHOOL

A 64.6-kg boy and a 49.1-kg girl, both wearing skates face each other at rest on a skating rink. The boy pushes the girl, sending her eastward with a speed of 3.57 m/s. Determine the subsequent speed (in m/s) of the boy. a. 2.7 m/s
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c. 31.8 m/s

Answers

Answer:

a. 2.7 m/s

Explanation:

Total momentum must be conserved before and after the push. Since they were both at rest before, their total speed, and momentum, is 0, so is the total momentum after the push

where are the mass of the boy and girl, respectively. are the velocities of the girl and boy after the push, respectively. We can solve for

So the boy speed is 2.7 m/s after pushing the girl

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a pulley of diameter 15.0 cm is driven by a motor that revolves at 10 rpm. the pulley drives a 2nd pulley with diameter 10.0 cm. find the rpm of the 2nd pulley

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6.67prm

diam1/diam2 = rpm1/rpm2
HIGH SCHOOL

During a free fall Swati was accelerating at -9.8m/s^2. After 120 seconds how far did she travel? Use the formula =1/2 * t^2 to solve your answer. (Do not forget to keep units in your answer.)

Answers

Answer: 70.56 km

From the Equation of motion:

where, is the distance covered, is the initial speed, is the acceleration and is the time.

In the question it is given that the Swati was in a free fall. This means that her initial velocity is 0 and she is just falling due to gravity. It means she is experiencing acceleration due to gravity. for time

Substitute the values in the equation of motion:

(ignore the negative sign)

COLLEGE

A small car with mass 0.800 kg travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m. if the normal force exerted by the track on the car when it is at the top of the track (point b.is 6.00 n, what is the normal force on the car when it is at the bottom of the track (point a)?

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I believe the answer is b .......
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